Optimal. Leaf size=220 \[ -\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}-i b e \text {Li}_2\left (1-\frac {2}{i c x+1}\right ) \left (a+b \tan ^{-1}(c x)\right )+i b e \text {Li}_2\left (\frac {2}{i c x+1}-1\right ) \left (a+b \tan ^{-1}(c x)\right )+2 e \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2-\frac {1}{2} b^2 c^2 d \log \left (c^2 x^2+1\right )+b^2 c^2 d \log (x)-\frac {1}{2} b^2 e \text {Li}_3\left (1-\frac {2}{i c x+1}\right )+\frac {1}{2} b^2 e \text {Li}_3\left (\frac {2}{i c x+1}-1\right ) \]
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Rubi [A] time = 0.46, antiderivative size = 220, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {4980, 4852, 4918, 266, 36, 29, 31, 4884, 4850, 4988, 4994, 6610} \[ -i b e \text {PolyLog}\left (2,1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )+i b e \text {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{2} b^2 e \text {PolyLog}\left (3,1-\frac {2}{1+i c x}\right )+\frac {1}{2} b^2 e \text {PolyLog}\left (3,-1+\frac {2}{1+i c x}\right )-\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}+2 e \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2-\frac {1}{2} b^2 c^2 d \log \left (c^2 x^2+1\right )+b^2 c^2 d \log (x) \]
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 266
Rule 4850
Rule 4852
Rule 4884
Rule 4918
Rule 4980
Rule 4988
Rule 4994
Rule 6610
Rubi steps
\begin {align*} \int \frac {\left (d+e x^2\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{x^3} \, dx &=\int \left (\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{x^3}+\frac {e \left (a+b \tan ^{-1}(c x)\right )^2}{x}\right ) \, dx\\ &=d \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2}{x^3} \, dx+e \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2}{x} \, dx\\ &=-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )+(b c d) \int \frac {a+b \tan ^{-1}(c x)}{x^2 \left (1+c^2 x^2\right )} \, dx-(4 b c e) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )+(b c d) \int \frac {a+b \tan ^{-1}(c x)}{x^2} \, dx-\left (b c^3 d\right ) \int \frac {a+b \tan ^{-1}(c x)}{1+c^2 x^2} \, dx+(2 b c e) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx-(2 b c e) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (2-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}-\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )+\left (b^2 c^2 d\right ) \int \frac {1}{x \left (1+c^2 x^2\right )} \, dx+\left (i b^2 c e\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx-\left (i b^2 c e\right ) \int \frac {\text {Li}_2\left (-1+\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}-\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )-\frac {1}{2} b^2 e \text {Li}_3\left (1-\frac {2}{1+i c x}\right )+\frac {1}{2} b^2 e \text {Li}_3\left (-1+\frac {2}{1+i c x}\right )+\frac {1}{2} \left (b^2 c^2 d\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (1+c^2 x\right )} \, dx,x,x^2\right )\\ &=-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}-\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )-\frac {1}{2} b^2 e \text {Li}_3\left (1-\frac {2}{1+i c x}\right )+\frac {1}{2} b^2 e \text {Li}_3\left (-1+\frac {2}{1+i c x}\right )+\frac {1}{2} \left (b^2 c^2 d\right ) \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )-\frac {1}{2} \left (b^2 c^4 d\right ) \operatorname {Subst}\left (\int \frac {1}{1+c^2 x} \, dx,x,x^2\right )\\ &=-\frac {b c d \left (a+b \tan ^{-1}(c x)\right )}{x}-\frac {1}{2} c^2 d \left (a+b \tan ^{-1}(c x)\right )^2-\frac {d \left (a+b \tan ^{-1}(c x)\right )^2}{2 x^2}+2 e \left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )+b^2 c^2 d \log (x)-\frac {1}{2} b^2 c^2 d \log \left (1+c^2 x^2\right )-i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+i b e \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )-\frac {1}{2} b^2 e \text {Li}_3\left (1-\frac {2}{1+i c x}\right )+\frac {1}{2} b^2 e \text {Li}_3\left (-1+\frac {2}{1+i c x}\right )\\ \end {align*}
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Mathematica [A] time = 0.39, size = 273, normalized size = 1.24 \[ -\frac {a^2 d}{2 x^2}+a^2 e \log (x)-\frac {a b d \left (\tan ^{-1}(c x)+c x \left (c x \tan ^{-1}(c x)+1\right )\right )}{x^2}+i a b e (\text {Li}_2(-i c x)-\text {Li}_2(i c x))-\frac {b^2 d \left (-2 c^2 x^2 \log \left (\frac {c x}{\sqrt {c^2 x^2+1}}\right )+\left (c^2 x^2+1\right ) \tan ^{-1}(c x)^2+2 c x \tan ^{-1}(c x)\right )}{2 x^2}+\frac {1}{24} b^2 e \left (24 i \tan ^{-1}(c x) \text {Li}_2\left (e^{-2 i \tan ^{-1}(c x)}\right )+24 i \tan ^{-1}(c x) \text {Li}_2\left (-e^{2 i \tan ^{-1}(c x)}\right )+12 \text {Li}_3\left (e^{-2 i \tan ^{-1}(c x)}\right )-12 \text {Li}_3\left (-e^{2 i \tan ^{-1}(c x)}\right )+16 i \tan ^{-1}(c x)^3+24 \tan ^{-1}(c x)^2 \log \left (1-e^{-2 i \tan ^{-1}(c x)}\right )-24 \tan ^{-1}(c x)^2 \log \left (1+e^{2 i \tan ^{-1}(c x)}\right )-i \pi ^3\right ) \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.50, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {a^{2} e x^{2} + a^{2} d + {\left (b^{2} e x^{2} + b^{2} d\right )} \arctan \left (c x\right )^{2} + 2 \, {\left (a b e x^{2} + a b d\right )} \arctan \left (c x\right )}{x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 7.81, size = 1313, normalized size = 5.97 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -{\left ({\left (c \arctan \left (c x\right ) + \frac {1}{x}\right )} c + \frac {\arctan \left (c x\right )}{x^{2}}\right )} a b d + a^{2} e \log \relax (x) - \frac {a^{2} d}{2 \, x^{2}} - \frac {12 \, b^{2} d \arctan \left (c x\right )^{2} - 3 \, b^{2} d \log \left (c^{2} x^{2} + 1\right )^{2} + {\left (3 \, {\left (c^{2} {\left (\frac {\log \left (c^{2} x^{2} + 1\right )^{2}}{c^{2}} - \frac {2 \, {\left (2 \, \log \left (c^{2} x^{2} + 1\right ) \log \relax (x) + {\rm Li}_2\left (-c^{2} x^{2}\right )\right )}}{c^{2}}\right )} - 2 \, {\left (\log \left (c^{2} x^{2} + 1\right ) - 2 \, \log \relax (x)\right )} \log \left (c^{2} x^{2} + 1\right )\right )} b^{2} c^{2} d + {\left (\log \left (c^{2} x^{2} + 1\right )^{3} - 3 \, \log \left (c^{2} x^{2} + 1\right )^{2} \log \left (-c^{2} x^{2}\right ) - 6 \, {\rm Li}_2\left (c^{2} x^{2} + 1\right ) \log \left (c^{2} x^{2} + 1\right ) + 6 \, {\rm Li}_{3}(c^{2} x^{2} + 1)\right )} b^{2} c^{2} d - 72 \, b^{2} c^{2} e \int \frac {x^{4} \arctan \left (c x\right )^{2}}{c^{2} x^{5} + x^{3}}\,{d x} - 192 \, a b c^{2} e \int \frac {x^{4} \arctan \left (c x\right )}{c^{2} x^{5} + x^{3}}\,{d x} - 72 \, b^{2} c^{2} d \int \frac {x^{2} \arctan \left (c x\right )^{2}}{c^{2} x^{5} + x^{3}}\,{d x} - b^{2} e \log \left (c^{2} x^{2} + 1\right )^{3} - 12 \, {\left ({\left (\arctan \left (c x\right )^{2} - \log \left (c^{2} x^{2} + 1\right ) + 2 \, \log \relax (x)\right )} c - 2 \, {\left (c \arctan \left (c x\right ) + \frac {1}{x}\right )} \arctan \left (c x\right )\right )} b^{2} c d + {\left (3 \, {\left (\log \left (c^{2} x^{2} + 1\right )^{2} \log \left (-c^{2} x^{2}\right ) + 2 \, {\rm Li}_2\left (c^{2} x^{2} + 1\right ) \log \left (c^{2} x^{2} + 1\right ) - 2 \, {\rm Li}_{3}(c^{2} x^{2} + 1)\right )} c^{2} - 6 \, {\left (\log \left (c^{2} x^{2} + 1\right ) \log \left (-c^{2} x^{2}\right ) + {\rm Li}_2\left (c^{2} x^{2} + 1\right )\right )} c^{2} - \frac {c^{2} x^{2} \log \left (c^{2} x^{2} + 1\right )^{3} - 3 \, {\left (c^{2} x^{2} + 1\right )} \log \left (c^{2} x^{2} + 1\right )^{2}}{x^{2}}\right )} b^{2} d + {\left (\log \left (c^{2} x^{2} + 1\right )^{3} - 3 \, \log \left (c^{2} x^{2} + 1\right )^{2} \log \left (-c^{2} x^{2}\right ) - 6 \, {\rm Li}_2\left (c^{2} x^{2} + 1\right ) \log \left (c^{2} x^{2} + 1\right ) + 6 \, {\rm Li}_{3}(c^{2} x^{2} + 1)\right )} b^{2} e - 72 \, b^{2} e \int \frac {x^{2} \arctan \left (c x\right )^{2}}{c^{2} x^{5} + x^{3}}\,{d x} - 192 \, a b e \int \frac {x^{2} \arctan \left (c x\right )}{c^{2} x^{5} + x^{3}}\,{d x} - 72 \, b^{2} d \int \frac {\arctan \left (c x\right )^{2}}{c^{2} x^{5} + x^{3}}\,{d x}\right )} x^{2}}{96 \, x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )}^2\,\left (e\,x^2+d\right )}{x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (c x \right )}\right )^{2} \left (d + e x^{2}\right )}{x^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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